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X^2=98X
We move all terms to the left:
X^2-(98X)=0
a = 1; b = -98; c = 0;
Δ = b2-4ac
Δ = -982-4·1·0
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9604}=98$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-98}{2*1}=\frac{0}{2} =0 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+98}{2*1}=\frac{196}{2} =98 $
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